Here is a random sample from normal distribution:
4,6,3,5,9,3
The question asks me to determine a 90% confidence interval. I know from that that the t-score is 2.015. The mean is 5.
In order to do the confidence interval, I have to have s. How do I find s?
Thank you!
Easy Statistics Question. How do I find S if all I have are samples and a confidence interval?
s = sqrt[(1/(n-1)) ∑(x - x*)²]
x is each of your items
n is the number of items
x* is the sample mean
You can do the work, but this is what you should get:
s = 2.28
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